PEARSON EDEXCEL · GCSE MATHEMATICS · 1MA1
Choose the right paper. Learn from every mark.
Use this collection of Edexcel GCSE Maths past papers and mark schemes to practise a complete exam, diagnose a weak topic or check a method. Start with the 1MA1 GCSE (9–1) papers at your entered tier. Older specifications are retained in a separate archive: they can supply extra topic practice, but their paper structure and grading do not match the current qualification.
Go straight to the paper and mark-scheme directory. You can also study six worked examples or try the eight-question diagnostic before choosing a full paper.
Independent HeLovesMath guidance, checked 5 October 2026. Exam papers and mark schemes belong to their respective copyright owners. Pearson publishes the qualification; some retained downloads are hosted by Save My Exams. This page is not an official Pearson service.
Which Edexcel Maths exam is this?
This guide concerns Pearson Edexcel GCSE (9–1) Mathematics, code 1MA1. Check the qualification code on your timetable or ask your teacher. GCSE 1MA1 is different from International GCSE Mathematics A (4MA1), International GCSE modular papers and legacy GCSE specifications. Similar-looking names do not make papers interchangeable.
Paper 2 and 3: calculator
Foundation papers have F in the code and assess grades 1–5. Higher papers have H and assess grades 4–9, with an allowed grade 3 outcome. An ungraded outcome is also possible. Foundation and Higher contain overlapping content, but they are different papers with different demands; a percentage from one tier should not be treated as the same grade on the other.
The papers draw on number; algebra; ratio, proportion and rates of change; geometry and measures; probability; and statistics. Topics are not reserved neatly for Paper 1, 2 or 3. Prepare the whole specification and practise choosing methods without a calculator as well as using one accurately.

Formula sheets and calculator preparation
Pearson provides separate Foundation and Higher exam-aid sheets. Use the sheet for your tier and exam series during realistic practice, and read any formulae supplied in the question. A formula sheet does not decide which formula applies, rearrange it or convert units for you.
Ofqual confirmed formula-sheet support for GCSE maths in 2025, 2026 and 2027, then announced on 5 May 2026 that it will continue from 2028 for the remaining lifetime of the current specifications. This does not mean that a future revised qualification must use an identical sheet. Pearson's current instructions and your exam centre remain the place to check the permitted materials for your own sitting. Official sources and tier-specific 2026 sheets are listed below.
Practise entering negative values with brackets, selecting the right angle mode and keeping intermediate results unrounded. Our scientific calculator guide can help you understand operations, but it is not a statement that any online calculator is permitted in an exam.
How to use the older archive
Use current 1MA1 papers first for timed practice. A legacy 1MA0 paper or an older Paper 3/4 may still contain useful arithmetic, algebra or geometry questions, but treat it as a topic bank. Do not use its time allowance, total marks or old letter-grade boundaries as a current 1MA1 mock.
Check the cover of every downloaded file for its qualification, tier, paper number and exam series. Match it to the corresponding mark scheme. Hosting filenames can be misleading, so a PDF's cover is stronger evidence than its URL alone. The directory notes any verified mismatch or access problem.
A useful revision cycle with past papers
- Choose a purpose. For an exam rehearsal, use a complete current-specification paper at your tier, with the correct calculator conditions. For a topic check, choose a few questions without pretending the partial score is a full-paper grade.
- Attempt before looking. Set out a calculation, a labelled diagram or a reason for each step. If you get stuck, note where the method stopped. A blank page and a nearly correct solution require different revision.
- Mark the method, not only the final number. Read the exact mark scheme and its general instructions. Method marks, accuracy marks and independent marks are not interchangeable; follow any dependencies and acceptable alternatives in that scheme. Do not award yourself marks merely because your working resembles the answer.
- Classify the error. Was it a missing fact, a wrong model, a sign or arithmetic slip, a unit error, a calculator entry, or incomplete justification? Write a one-sentence correction and redo the question without copying the solution.
- Retest with a fresh question. First try a similar question while the idea is clear. Then return to it later without the worked solution. Correcting one remembered answer is weaker evidence than solving a new example.
For targeted follow-up, use the GCSE algebra worksheets, probability worksheets and statistics worksheets. Pick the topic your attempted paper exposed rather than completing resources at random.
Track marks without inventing a grade
A practice score of 52/80 is 65%, because 52 ÷ 80 × 100 = 65. That arithmetic does not by itself identify a GCSE grade. For a full series, add the marks on all three papers at the same tier and use that series' official qualification grade boundaries as a historical comparison. Boundaries can change between series; a past boundary is not a promise for a future exam.
For time management, 90 ÷ 80 = 1.125 minutes per mark, or 67.5 seconds. This is a rough planning average, not a rule for every question. Some short questions can be completed quickly; multi-step reasoning needs longer. Leave time to check signs, units and whether you answered the question actually asked.
Six worked examples to sharpen your methods
Original HeLovesMath practice, not Pearson past-paper questions or an official mark scheme. Calculator labels describe how to practise these examples, not which numbered exam paper will contain a topic.
1: subtracting fractions
Topic: Number. Suitable for: Foundation and Higher. Method: Non-calculator.
Question: Work out 5/6 − 3/8. Give your answer as a fraction in its simplest form.
Solution:
- The lowest common denominator of 6 and 8 is 24.
- Rewrite each fraction: 5/6 = 20/24 and 3/8 = 9/24.
- Subtract the numerators: 20/24 − 9/24 = 11/24.
- Since 11 and 24 have no common factor greater than 1, this is already simplest form.
Check: 5/6 is about 0.83 and 3/8 is 0.375, so the result should be just under 0.5. The fraction 11/24 has that size.
Common mistake: Subtracting the denominators. Equivalent fractions must share a denominator before adding or subtracting.
2: reversing a percentage decrease
Topic: Ratio, proportion and rates of change. Suitable for: Foundation and Higher. Method: Either paper style.
Question: A jacket costs £68 after a 15% reduction. What was its original price?
Solution:
- After the reduction, the jacket costs 100% − 15% = 85% of its original price.
- Write an equation: 0.85 × original price = 68.
- Divide by the multiplier: original price = 68 ÷ 0.85 = £80.
Check: 15% of £80 is £12, and £80 − £12 = £68.
Common mistake: Adding 15% of £68. The discount was calculated from the unknown original price, not from £68.
3: using the quadratic formula
Topic: Algebra. Suitable for: Higher. Method: Calculator for the decimal answers.
Question: Solve 2x² + 5x − 4 = 0. Give both solutions to 3 significant figures.
Solution:
- Identify a = 2, b = 5 and c = −4.
- Use x = (−b ± √(b² − 4ac)) / (2a).
- Substitute carefully: x = (−5 ± √(25 − 4 × 2 × (−4))) / 4.
- The discriminant is 25 + 32 = 57, so x = (−5 ± √57) / 4.
- The two calculator values are 0.6374586… and −3.1374586… .
- To 3 significant figures: x = 0.637 or x = −3.14.
Check: The exact roots have sum −5/2 and product −2, matching −b/a and c/a. Substituting the unrounded roots also returns zero.
Common mistakes: Using c = 4 instead of −4, losing the plus/minus branch, or dividing only the square-root term by 4. Keep the whole numerator in brackets when entering the expression.
4: choosing the cosine rule
Topic: Geometry and measures. Suitable for: Higher. Method: Calculator in degree mode.
Question: Two sides of a triangle are 7 cm and 10 cm. The angle between them is 48°. Find the length of the third side to 3 significant figures.
Solution:
- The known information is two sides and their included angle, so use the cosine rule.
- Let a be the side opposite 48°: a² = 7² + 10² − 2 × 7 × 10 × cos 48°.
- Evaluate without rounding the cosine first: a² = 149 − 140 cos 48° = 55.321715… .
- Take the positive square root: a = 7.437856… .
- The third side is 7.44 cm to 3 significant figures.
Check: A triangle with sides 7 and 10 must have its third side between 3 and 17. The answer satisfies this; the cosine calculation is also positive.
Common mistakes: Using Pythagoras when the angle is not 90°, using radians, or forgetting to take the square root.
5: probability without replacement
Topic: Probability. Suitable for: Higher practice. Method: Exact fractions; non-calculator friendly.
Question: A bag contains 5 red counters and 3 blue counters. Two counters are selected at random without replacement. Find the probability of selecting exactly one blue counter.
Solution:
- Exactly one blue can happen in two orders: blue then red, or red then blue.
- P(blue then red) = (3/8) × (5/7) = 15/56.
- P(red then blue) = (5/8) × (3/7) = 15/56.
- The two orders cannot both happen in one trial, so add their probabilities: 15/56 + 15/56 = 30/56 = 15/28.
Check: The complementary events are two red and two blue. Their probabilities total (5/8 × 4/7) + (3/8 × 2/7) = 26/56. Then 1 − 26/56 = 30/56, agreeing with the answer.
Common mistakes: Leaving 8 in the second denominator despite removing a counter, or counting only one order.
6: mean from a frequency table
Topic: Statistics. Suitable for: Foundation and Higher. Method: Either paper style.
Question: Ten students report how many books they finished in one month. Two students read 0 books; four read 1; three read 2; one read 3. Find the mean number of books.
Solution:
- Multiply each number of books by its frequency: 0 × 2 = 0, 1 × 4 = 4, 2 × 3 = 6, 3 × 1 = 3.
- Total books = 0 + 4 + 6 + 3 = 13.
- Total students = 2 + 4 + 3 + 1 = 10.
- Mean = total books ÷ total students = 13/10 = 1.3 books per student.
Check: The mean is between 0 and 3. It does not have to be a whole number, even though each individual count is a whole number.
Common mistake: Dividing by 4 because there are four categories. Divide by the total frequency, 10.
Eight questions: try first, then check
Questions 1–6 cover skills useful to both tiers. Questions 7–8 extend into Higher material. Show your working before opening each solution. This is a diagnostic exercise, not a mini-paper or grade predictor.
1. Fractions — Foundation/Higher, non-calculator
Calculate (3/4 + 2/5) ÷ (3/2). Give your answer in simplest form.
Show answer 1
First add the fractions using denominator 20: 3/4 + 2/5 = 15/20 + 8/20 = 23/20. Dividing by 3/2 means multiplying by 2/3: (23/20) × (2/3) = 46/60 = 23/30. The brackets require the addition before the division.
2. Standard form — Foundation/Higher, non-calculator
Calculate (4.8 × 10⁵) ÷ (1.6 × 10²). Give your answer in standard form.
Show answer 2
Divide the coefficients and subtract the powers: (4.8 ÷ 1.6) × 10^(5 − 2) = 3 × 10³. The coefficient 3 is at least 1 and less than 10, so the result is in standard form.
3. Sharing in a ratio — Foundation/Higher, non-calculator
£126 is shared between Alex, Bea and Chen in the ratio 2 : 5 : 7. How much does each person receive?
Show answer 3
There are 2 + 5 + 7 = 14 equal parts. One part is £126 ÷ 14 = £9. Alex receives £18, Bea £45, and Chen £63. Check: 18 + 45 + 63 = 126.
4. Linear equation — Foundation/Higher, non-calculator
Solve 4(2x − 3) = 5x + 9.
Show answer 4
Expand: 8x − 12 = 5x + 9. Subtract 5x and add 12: 3x = 21. Hence x = 7. Check: 4(14 − 3) = 44 and 35 + 9 = 44.
5. Pythagoras — Foundation/Higher, non-calculator friendly
A right-angled triangle has hypotenuse 13 cm and one shorter side 5 cm. Find the other shorter side.
Show answer 5
Let the missing shorter side be b. Pythagoras gives 5² + b² = 13², so b² = 169 − 25 = 144. Take the positive root because b is a length: b = 12 cm. Subtract the known square from the hypotenuse square; do not add them when finding a shorter side.
6. Interpreting data — Foundation/Higher, non-calculator
The six values in a data set are 4, 7, 7, 9, 13 and 14. Find the median and the range.
Show answer 6
The values are already ordered. With six values the middle positions are third and fourth: median = (7 + 9) ÷ 2 = 8. Range = largest − smallest = 14 − 4 = 10. The repeated 7 still occupies two separate positions.
7. Linear–quadratic simultaneous equations — Higher
Solve the equations y = x + 1 and x² + y² = 25. Give both ordered pairs (x, y).
Show answer 7
Substitute y = x + 1 into the second equation: x² + (x + 1)² = 25. Expand and simplify: 2x² + 2x + 1 = 25, then 2x² + 2x − 24 = 0. Divide by 2: x² + x − 12 = 0. Factorise: (x + 4)(x − 3) = 0. Thus x = −4 or x = 3. Substituting into y = x + 1 gives (−4, −3) and (3, 4). Both pairs satisfy x² + y² = 25.
8. Histogram frequency density — Higher
A grouped table records waiting time t in minutes for 28 customers:
0 ≤ t < 10: frequency 6; 10 ≤ t < 25: frequency 12; 25 ≤ t ≤ 45: frequency 10.
Find the frequency density for each interval and state which histogram bar would be tallest.
Show answer 8
The class widths are 10, 15 and 20 minutes. Frequency density = frequency ÷ class width, so the densities are 0.6, 0.8 and 0.5 customers per minute, respectively. The 10 ≤ t < 25 bar is tallest because its density is greatest. In a histogram, bar area represents frequency; height alone represents density. Check: 0.6 × 10 + 0.8 × 15 + 0.5 × 20 = 28 customers.
See why the missing side matters
The diagram below finds the hypotenuse from two perpendicular sides. Question 5 reverses the process: because 13 cm is already the hypotenuse, subtract 5² from 13² to find the missing shorter side squared. Pythagoras applies to a right-angled triangle, not every triangle.

Sources & References
The official sources below support the qualification, formula-sheet and grading guidance. The paper directory follows them. External links open in a new tab. Downloads remain on their original hosts; no third-party papers have been rehosted.
- Pearson 1MA1 specification, qualification overview, content weightings and assessment summary
- Ofqual: what schools and colleges need to know before exams
- Ofqual: GCSE and A level grading
- Ofqual's decision for 2025, 2026 and 2027
- Ofqual's decision for the lifetime of current specifications
- 2026 Foundation tier exam aid, Pearson PDF
- 2026 Higher tier exam aid, Pearson PDF
- Pearson GCSE Mathematics course materials
- Pearson's April 2026 update
- Pearson: important information on the provision of formulae in GCSE Mathematics
Past-paper and mark-scheme directory
Choose your qualification and tier, then search for a session such as June 2023. The archive retains all 250 original download destinations. Some series are incomplete: June 2019 Foundation Paper 2 and its scheme are not present, and the current-specification June 2017 subset contains Paper 3 only. Check Pearson’s course-materials hub above for newer releases and additional official papers.
Important pairing correction: two retained June 2016 Foundation mark-scheme URLs lead to International GCSE 4MA0 documents, whereas the question papers are GCSE 1MA0. Those links are visibly labelled as mismatched and must not be used to mark the adjacent question paper. The June 2017 Paper 3 downloads are correctly grouped as current 1MA1.
125 paper entries, each retaining its original question and reference-scheme links.
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